Prove that if $d\cdot e| d(d+1)+e\cdot e$ then $d\cdot (d+1)+e\cdot e=3de$

Prove that if $d\cdot e| d(d+1)+e\cdot e$ then $d\cdot (d+1)+e\cdot e=3de$

Prove that if $d\cdot e| d(d+1)+e\cdot e$ then $d\cdot (d+1)+e\cdot e=3de$
where $d$ and $e$ are positive integers.